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S(ABCD)≤AC*BD/2≤(PA+PC)(PB+PD)/2=(24+28)(32+45)/2=26*77=2002∵S(ABCD)=2亚界候术言便吗002∴AC⊥BD,AC与BD交于P。∴AB=√(PA?+PB?)=√(24?+32?)=40BC=√(PB?+PC?)=√(32?+28?)=4√113CD=√(PC?+PD?)=√(28?+45?)=53DA=√(PD?+PA?)=√须核(45?+24?)=51ABCD周长=AB+BC+CD+DA来自=144+4√113